We will try to discuss pertahap: sodium carbonate: Na + + CO 3 2- Na 2 CO 3 sulfuric acid: H

Previously been discussed several issues equalization equation. Problems that are supplied in the form of the equation so we just equalizes duty alone. So what if a matter of just a story about substances reactants and reaction products? Yes, of course we must be observant arrange the equation first. In matters like this is your seriousness in studying cations and anions to fruition. You will realize that what you have learned is not in vain. While some students have difficulty constructing rtu a reaction equation because they did not know the cation, anion, or elements of a substance pembetuk apada matter. Therefore, if you are a person who has been struggling to understand the anions, cations, and identify the elements, then enjoy the ease that you earn. But if you did not understand what was cations and anions, then you should start to care, even if you feel it is not important.
Questions and discussion Write the equivalent rtu equations for each of the following reactions. Sodium carbonate solution with a solution of sulfuric acid to form sodium sulfate, carbon dioxide, and water. Solution of lead (II) acetate with a solution of potassium iodide solution forms a precipitate of lead (II) iodide and potassium acetate. Solution of ammonium sulfate with sodium hydroxide solution to form a solution natriun sulfate, ammonia gas, and water. Iron with hydrochloric acid to form iron (II) chloride and hydrogen gas. Iron (III) oxide solid with a solution of sulfuric acid to form a solution of iron (III) sulfate rtu and water. Carbon dioxide gas with a solution of potassium hydroxide to form a solution of potassium carbonate and water. Aluminum metal with sulfuric acid to form a solution of aluminum sulfate and hydrogen gas. Pentaoksida Diposforus solid with a solution of potassium hydroxide to form a solution of potassium phosphate and water. Powdered potassium chlorate with sulfur powder form solid potassium chloride and sulfur dioxide gas. Solution of copper (II) sulfate with sodium hydroxide solution to form precipitate of copper (II) hydroxide and sodium sulphate.
We will try to discuss pertahap: sodium carbonate: Na + + CO 3 2- Na 2 CO 3 sulfuric acid: H + + SO 4 2- H 2 SO 4 sodium sulphate: Na + + SO 4 2- Na 2 SO 4 carbon dioxide: CO 2 water = H 2 O Then the equation is: Na 2 CO 3 + H 2 SO 4 Na 2 SO 4 + CO 2 + H 2 O Na 2 CO 3 + H 2 SO 4 Na 2 SO 4 + CO 2 + H 2 O Check: rtu Na = 2; C = 1; S = 1; H = 2; O = 7. Description: phase substances you can add yourself.
We will try to discuss pertahap: lead (II) acetate: Pb 2+ + CH 3 COO - Pb (CH 3 COO) 2 potassium iodide: K + + I - KI lead (II) iodide: Pb 2+ + I - PBI 2 potassium acetate: rtu K + + CH 3 COO - CH 3 COOK So the equation is: Pb (CH 3 COO) 2 + KI PBI 2 + CH 3 COOK Pb (CH 3 COO) 2 + KI PBI 2 + 2 CH 3 COOK Pb (CH 3 COO) 2 + 2 KI PBI 2 + 2 CH 3 COOK Check: Pb = 1; C = 4; K = 2; I = 2; H = 6; O = 8.
We will try to discuss pertahap: ammonium sulphate: NH 4 + + SO 4 2- (NH 4) 2 SO 4 sodium hydroxide: Na + + OH - NaOH natriun sulphate: Na + + SO 4 2- Na 2 SO 4 ammonia: NH 3 water = H 2 O Then the equation is: (NH 4) 2 SO 4 + NaOH Na 2 SO 4 + 2 NH 3 + H 2 O (NH 4) 2 SO 4 + 2 NaOH Na 2 SO 4 + 2NH 3 + H 2 O (NH 4) 2 SO 4 + 2 NaOH Na 2 SO 4 + 2 NH 3 + 2 H 2 O (NH 4) 2 SO 4 + 2 NaOH Na 2 SO 4 + 2NH 3 + 2 H 2 O Check: N = 2; S = 1; Na = 2; H = 10; O = 6.
We will try to discuss pertahap: Iron: Fe hydrochloric acid: H + + Cl - HCl iron (II) chloride: Fe 2+ + Cl - FeCl 2 hydrogen: H 2 Then the equation is: Fe + HCl FeCl 2 + H 2 Fe + 2 HCl FeCl 2 + H 2 Check: Fe = 1; Cl = 2; H = 2.
We will try to discuss pertahap: Iron (III) oxide: Fe 3+ + O 2- Fe 2 O 3 sulfuric acid: H + + SO 4 2- H 2 SO 4 iron (III) sulphate: Fe 3 + + SO 4 2- Fe 2 (SO 4) 3 water = H 2 O Then the equation is: Fe 2 O 3 + H 2 SO 4 Fe 2 (SO 4) 3 + H 2 O Fe 2 O 3 + 3 H 2 SO 4 Fe 2 (SO 4) 3 + H 2 O Fe 2 O 3 + 3 H 2 SO 4 Fe 2 (SO 4) 3 + 3 H 2 O Fe 2 O 3 + 3 H 2 SO 4 Fe 2 (SO 4) 3 + 3 H 2 O Check: Fe = 2; S = 3; H = 6; O = 15.
We will try to discuss pertahap: carbon oxides: CO 2 potassium hydroxide: K + + OH - potash KOH: K + + CO 3 2- K 2 CO 3 water = H 2 O Then the equation